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How do you graph #y-4x=0# by plotting points?

Answer 1

see below

By adding #4x# on both sides of the equation, we obtain #y=4x#. We can plot point in the #xy#-plane by choosing values of #x#.

For example, let's choose #x=-2, -1, 0, 1, #and #2# for simplicity. When: #x=-2#, #y=4(-2)=-8#, so the point is #(-2,-8)#. #x=-1#, #y=4(-1)=-4#, so the point is #(-1,-4)#. #x=0#, #y=4(0)=0#, so the point is #(0,0)#. #x=1#, #y=4(1)=4#, so the point is #(1,4)#. #x=2#, #y=4(2)=8#, so the point is #(2,8)#.

The graph should look something like this after you plot the points and connect the points from above. graph{y=4x [-5, 5, -10, 10]}

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Answer 2

Isaiah Anthony

To graph ( y - 4x = 0 ) by plotting points, you can choose values for ( x ), calculate the corresponding ( y ) values using the equation, and then plot the points on a coordinate plane. Alternatively, you can rearrange the equation to solve for ( y ), yielding ( y = 4x ), which is in slope-intercept form. From there, you can identify the slope (4) and the y-intercept (0), and use this information to plot the graph.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.