# How do you graph #y < 3x+5# and # y> -3x +2#?

Graph and solve the system:

(1) y < 3x + 5

(2) y > -3x + 2

First, graph the line y1 = 3x + 5 by its two intercepts. Set x = 0 --> y = 5. Set y = 0 --> x = -5/3>. The area below the line y1 represents the solution set of inequality (1). Next, graph the line y2 = - 3x + 2 by its two intercepts. The area above the Line y2 represents the solution set of inequality (2). Finally, color or shade the compound solution set.

graph{3x + 2 [-10, 10, -5, 5]} and graph{3x + 5 [-10, 10, -5, 5]}

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