How do you graph #y < 3x+5# and # y> -3x +2#?

Answer 1

Graph and solve the system:
(1) y < 3x + 5
(2) y > -3x + 2

First, graph the line y1 = 3x + 5 by its two intercepts. Set x = 0 --> y = 5. Set y = 0 --> x = -5/3>. The area below the line y1 represents the solution set of inequality (1). Next, graph the line y2 = - 3x + 2 by its two intercepts. The area above the Line y2 represents the solution set of inequality (2). Finally, color or shade the compound solution set.

graph{3x + 2 [-10, 10, -5, 5]} and graph{3x + 5 [-10, 10, -5, 5]}

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Answer 2
To graph the inequalities \(y < 3x + 5\) and \(y > -3x + 2\): 1. Graph the line \(y = 3x + 5\) as a dashed line (since it's \(y <\) not \(y \leq\)). Use a slope of \(3\) and a y-intercept of \(5\). 2. Shade the region below the line \(y = 3x + 5\), since it's \(y < 3x + 5\). 3. Graph the line \(y = -3x + 2\) as a dashed line (since it's \(y >\) not \(y \geq\)). Use a slope of \(-3\) and a y-intercept of \(2\). 4. Shade the region above the line \(y = -3x + 2\), since it's \(y > -3x + 2\). The region where both shaded areas overlap represents the solution to the system of inequalities.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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