How do you graph #y=3x-2# by plotting points?
Plug in a value of x in to the equation. The resulting value is its pair. Have two or three pairs. Plot these points in a Cartesian plane. Connect the points.
Choose any value of x. But, to make it simpler, lets use the values: 0, 1, and 2.
then we plot these points and connect them and have this: graph{3x-2 [-5, 5, -2.5, 2.5]}
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To graph ( y = 3x - 2 ) by plotting points:
- Choose some values for ( x ) (e.g., -2, -1, 0, 1, 2).
- Substitute each value of ( x ) into the equation to find the corresponding ( y ) values.
- Plot the points ( (x, y) ) on the coordinate plane.
- Connect the points with a straight line.
For example:
- When ( x = -2 ), ( y = 3(-2) - 2 = -6 - 2 = -8 ), so the point is (-2, -8).
- When ( x = -1 ), ( y = 3(-1) - 2 = -3 - 2 = -5 ), so the point is (-1, -5).
- When ( x = 0 ), ( y = 3(0) - 2 = 0 - 2 = -2 ), so the point is (0, -2).
- When ( x = 1 ), ( y = 3(1) - 2 = 3 - 2 = 1 ), so the point is (1, 1).
- When ( x = 2 ), ( y = 3(2) - 2 = 6 - 2 = 4 ), so the point is (2, 4).
Plotting these points and connecting them will give you the graph of ( y = 3x - 2 ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- What is the slope of the line passing through the following points: # (2,6) ; (-4,-2)#?
- How do you find the slope of the line containing the indicated points: ( -10, -4) and ( -3, -3)?
- How do you find the slope given #y= -2/3x + 1#?
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