How do you graph #y=3x^2+6x-1#?
A quadratic function represents a parabola, hence its vertex and the axis of symmetry can be found from the given equation as follows
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To graph the quadratic equation y = 3x^2 + 6x - 1, you can follow these steps:
- Plot the vertex of the parabola, which is located at the point (-b/2a, f(-b/2a)).
- Determine the axis of symmetry, which is the vertical line passing through the vertex.
- Find at least two additional points on either side of the vertex to sketch the parabola accurately.
- Plot these points and draw a smooth curve through them to represent the graph of the equation.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- How do you solve using the completing the square method #x^2-8x+15=0#?

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