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How do you graph #y = 3( x + 1 )^2-4#?

Answer 1

Nathan Axel

graph{3(x+1)^2-4 [-10, 10, -5, 5]}

This equation is in vertex form, which is #a(x-h)^2+k#, in which #(h,k)# is the vertex.

In this case, the vertex for this equation is #(-1,4)#

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Answer 2

Eli Assouline

To graph the equation y = 3(x + 1)^2 - 4, you can start by identifying the vertex, which is (-1, -4). Then, use the coefficient of x^2 (which is 3) to determine the direction of the parabola (upward because it's positive). Next, plot additional points symmetrically around the vertex to sketch the parabola accurately.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.