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How do you graph #y = -3/2x + 2#?

Answer 1

Genesis Allen

See a solution process below:

Plot the first two points that are found by solving the equation:

First Point: For #x = 0#

#y = (-3/2 * 0) + 2#

#y = 0 + 2#

#y = 2# or #(0, 2)#

Second Point: For #x = 2#

#y = (-3/2 * 2) + 2#

#y = -3 + 2#

#y = -1# or #(2, -1)#

Next, we can chart the two points on the coordinate plane as follows:

graph{(x^2+(y-2)^2-0.035)((x-2)^2+(y+1)^2-0.035)=0 [-10, 10, -5, 5]}

To graph the line, we can now draw a straight line through the two points as follows:

graph{(x^2+(y-2)^2-0.035)((x-2)^2+(y+1)^2-0.035)=0 [-10, 10, -5, 5]}

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Answer 2

Jace Anderson

To graph the equation y = -3/2x + 2, plot the y-intercept at (0, 2), then use the slope -3/2 to find another point. Repeat to draw the line.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.