# How do you graph #y=2x+6#?

graph{y=2x+6 [-10, 10, -5, 5]} graph{2x+6 [-22.68, 22.69, -11.82, 11.82]}

To begin, plot your y intercept on your graph. In your equation, your y intercept would be +6.

Next, from your y intercept, you'll want to insert your slope. In your equation, your slope is +2 (or, 2/1). To do this, you're going to want to go to the left once (run) and up twice (rise).

Continue this pattern and extend your line through your graph.

You should get something similar to the graph above.

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To graph the equation ( y = 2x + 6 ), you can start by plotting the y-intercept, which is 6 on the y-axis. Then, use the slope, which is 2, to find another point. Since the slope is the coefficient of ( x ), it means for every 1 unit increase in ( x ), ( y ) increases by 2 units. So, from the y-intercept, move 1 unit to the right and 2 units up. Connect the two points with a straight line to complete the graph.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- Is the equation #6x^2+3y=0# an example of direct variation?

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