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How do you graph #y< 2^(x-4)#?

Answer 1

Elias Ackerman

See graph and explanation.

#y<2^x 2^(-4)=1/16(2^x) #

The inequality's region, { ( x, y ) }, is situated beneath the boundary curve.

#y = 1/16 (2^x) > 0. y to 0# as #x to -oo and to oo#, as x to oo#,

with y-intercept # ( x = 0 ) = 1/16#.

As #y'= ln 2 (2^x) > 0, y uarr# as x #uarr.#

graph{y-2^x/16<0 [-4.296, 4.207, 8.5, -8.514]}

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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How do you graph #y&lt; 2^(x-4)#?

How do you graph #y< 2^(x-4)#?