How do you graph #y= -2/3x +4# by plotting points?
See a solution process below:
Plot the first two points that are found by solving the equation:
Next, we can chart the two points on the coordinate plane as follows:
graph{(x^2+(y-4)^2-0.04)((x-3)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}
To graph the line, we can now draw a straight line through the two points as follows:
graph{(y + (2/3)x-4)(x^2+(y-4)^2-0.04)((x-3)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}
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To graph ( y = -\frac{2}{3}x + 4 ) by plotting points, you can choose values for ( x ), calculate corresponding ( y ), and then plot the points on a coordinate plane. Choose at least two or three values for ( x ), such as ( x = 0, 3, ) and ( -3 ), then calculate the corresponding ( y ) values using the equation. Plot the points ( (x, y) ), and then draw a line through them to represent the graph of the equation.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- What is the slope of the line passing through the following points: #(3, 5) ,(-4, 1) #?
- What is the slope and y-intercept of this line #y= -2#?
- What is the slope of the line passing through the following points: #(4,-1) , (-5, 2) #?
- How do you graph #Y=2^x+3# by plotting points?
- What is the slope of the line between # (6, 13) # and # (14, -2 ) #?
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