How do you graph #y>=1/5x+10# on the coordinate plane?

First, solve for two points as an equation instead of a inequality to find the boundary line for the inequality.

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.

The boundary line will be solid because the inequality operator contains a "or equal to" clause.

graph{(y-1/5x-10)((x+10)^2+(y-8)^2-0.3)(x^2+(y-10)^2-0.3)=0 [-30, 30, -15, 15]}

To complete the chart of the inequality we shade the left side of the line:

graph{(y-1/5x-10)>=0 [-30, 30, -15, 15]}

To graph ( y \geq \frac{1}{5}x + 10 ) on the coordinate plane, first, plot the y-intercept, which is at the point (0, 10). Then, use the slope of ( \frac{1}{5} ) to find another point. Since the inequality is ( y \geq \frac{1}{5}x + 10 ), the line will be solid (not dashed) and shaded above the line because of the "greater than or equal to" symbol.