How do you graph #y= (1/2)x# by plotting points?
So if y=1/2x, then x=2y.
graph{1/2(x) [-10, 10, -5, 5]}
It's best to only plot whole numbers because then your line will be perfectly straight. If you plot 2 for x, then plug 2 into the equation: 2=2y. Then solve. y=1. So the first co-ordinate would be (2,1). Just continue that and you'll be good! And it works for any fraction. If your y= equation is already whole, then you're gucci!
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Additional tip
Straight line graph is very straight forward.
Technically you could calculate just two pints and draw the line through them. This potentially has a problem. Suppose you made a mistake. It is much better to calculate three points. If they all do not line up then you have gone wrong somewhere.
Now you plot each one against the other
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To graph the equation y = (1/2)x by plotting points, you can choose values for x and calculate corresponding values for y using the equation. For example:
When x = 0, y = (1/2)(0) = 0 When x = 2, y = (1/2)(2) = 1 When x = 4, y = (1/2)(4) = 2 When x = -2, y = (1/2)(-2) = -1 When x = -4, y = (1/2)(-4) = -2
Plot these points on a coordinate plane and then connect them to form a straight line.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- How do you find the x and y intercepts for #4x - 1/3y = -2#?
- How to find the #y#-intercept of the line # y=x+2#?
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