How do you graph #y=0.25x-2# using a table of values?

Question

Abigail Allen · Accepted Answer

Generate a table of #(x,y)# coordinates using several (arbitrary, but convenient) values for #x#;
plot these coordinates;
connect the plotted points with a line.

To simplify the coordinates, I would suggest using using values of #x# which are multiples of #4# (so #0.25x# will an integer). Here are some possibilities: #{: (color(red)(x)," | ",color(blue)(y=0.25x-2)), (bar(color(white)("XXXX")),,bar(color(white)("XXXXXXXXXX"))), (-4," | ",-3), (color(white)("X")0," | ",-2), (color(white)("X")4," | ",-1), (color(white)("X")8," | ",color(white)("X")0), (12," | ",color(white)("X")1) :}# Plotting the points: graph{((x+4)^2+(y+3)^2-0.02)(x^2+(y+2)^2-0.02)((x-4)^2+(y+1)^2-0.02)((x-8)^2+y^2-0.02)((x-12)^2+(y-1)^2-0.02)=0 [-9.35, 15.96, -6.85, 5.81]} Connected with a line: graph{((x+4)^2+(y+3)^2-0.02)(x^2+(y+2)^2-0.02)((x-4)^2+(y+1)^2-0.02)((x-8)^2+y^2-0.02)((x-12)^2+(y-1)^2-0.02)(0.25*x-2-y)=0 [-9.35, 15.96, -6.85, 5.81]}

Ethan Adkins · Answer

undefined To graph the equation $ y = 0.25x - 2 $ using a table of values, you can choose several values for $ x $, plug them into the equation to find the corresponding $ y $ values, and then plot those points on a coordinate plane.

| $ x $ | $ y $ |
|--------|--------|
| -8     | -4     |
| -4     | -3     |
| 0      | -2     |
| 4      | -1     |
| 8      | 0      |

After obtaining the values, plot the points (-8, -4), (-4, -3), (0, -2), (4, -1), and (8, 0) on a graph, and then draw a straight line passing through these points.