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How do you graph #x+y=5# using intercepts?

Answer 1

Eva Abramson

Plot points and connect the dots.

First, plot the #x# intercept. You get this by setting #y=0#.

#x+0=5#

#x=5#

This gives the point #(5,0)#, plotted here:

graph{((x-5)^2+(y-0)^2 - 1/100)=0 [-1.904, 15.874, -3.68, 5.21]}

Next, plot the #y# intercept. You get this by setting #x=0#.

#0+y=5#

#y=5#

This gives the point #(0,5)#, plotted here:

graph{((x-5)^2+(y-0)^2 - 1/100)((x-0)^2+(y-5)^2 - 1/100)=0 [-1.904, 15.874, -3.68, 5.51]}

Finally, draw a line connecting the two points on the graph. The solution looks like this:

graph{((x-5)^2+(y-0)^2 - 1/100)((x-0)^2+(y-5)^2 - 1/100)(x+y-5)=0 [-1.904, 15.874, -3.68, 5.51]}

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Answer 2

Avery Alexander

To graph the equation (x + y = 5) using intercepts:

Find the x-intercept by setting (y = 0) and solving for (x). (x + 0 = 5), (x = 5).
Find the y-intercept by setting (x = 0) and solving for (y). (0 + y = 5), (y = 5).
Plot the points (5, 0) and (0, 5) on the coordinate plane.
Draw a straight line through the points to represent the graph of (x + y = 5).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.