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How do you graph #x+y ≤ 5+2# and #y > 2#?

Answer 1

You can modify the first equation by subtracting #x# from both sides

We need everything below AND including this straight line, #y<=5-x# graph{5-x [-4.875, 15.125, -1.36, 8.64]}

The line #y=2# is a straight horizontal one, and we want everything above it—that is, everything OTHER than the line itself.

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Answer 2

Eva Adamson

To graph the inequality (x + y \leq 5) and (y > 2), you would start by graphing the line (x + y = 5), which represents the boundary of the first inequality. Then, you would shade the region below the line because it satisfies the inequality (x + y \leq 5). Next, you would draw a dashed line at (y = 2), representing the boundary of the second inequality. Finally, you would shade the region above the line because it satisfies the inequality (y > 2). The area where the two shaded regions overlap represents the solution to both inequalities.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you graph #x+y ≤ 5+2# and #y &gt; 2#?

How do you graph #x+y ≤ 5+2# and #y > 2#?