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How do you graph #x-y=3 #?

Answer 1

You must first put the equation into slope-intercept form (y = mx + b). To do this, subtract x from both sides to isolate y. Then, since y will be negative, divide each side by -1, resulting in y = x - 3. Since a 1 is understood to be in front of the x, the slope is 1. Also, the y-intercept will be (0, -3).

x - y = 3. Subtract x from both sides. -y = -x + 3. Divide each side by -1. Y = x -3. Plot the y-intercept (0, -3). To find other points, substitute any number in for x and solve for the y value. (ex: points (2, -1) and (-4, -7).

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Answer 2

Jace Anderson

To graph the equation (x - y = 3), you can rearrange it into slope-intercept form (y = mx + b), where (m) is the slope and (b) is the y-intercept. Solving for (y), we get (y = x - 3). Now, we can plot the y-intercept at ((0, -3)) and use the slope of 1 (since the coefficient of (x) is 1) to find additional points. Connecting these points will give us the graph of the equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.