How do you graph #(x+5)^2+(y2)^2=9#?
This is a circle with centre
Given:
This can be rewritten slightly as:
which is in the standard form:
graph{((x+5)^2+(y2)^29)((x+5)^2+(y2)^20.02) = 0 [15.75, 4.25, 3.12, 6.88]}
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To graph the equation ( (x+5)^2 + (y2)^2 = 9 ), which represents a circle, follow these steps:

Identify the center of the circle from the equation ( (xh)^2 + (yk)^2 = r^2 ), where (h, k) is the center of the circle and r is the radius. In this case, the center is (5, 2).

Determine the radius of the circle. In the equation ( (x+5)^2 + (y2)^2 = 9 ), the radius is 3 because ( r^2 = 9 ) implies ( r = 3 ).

Plot the center of the circle at (5, 2) on the coordinate plane.

Using the radius of 3 units, mark points on the circle. You can do this by going 3 units to the right, left, up, and down from the center to find the points on the circle.

Connect these points smoothly to draw the circle.

Label the center and any other relevant points, such as the points where the circle intersects the axes if applicable.
By following these steps, you'll accurately graph the circle represented by the equation ( (x+5)^2 + (y2)^2 = 9 ) on the coordinate plane.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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 A triangle has vertices A, B, and C. Vertex A has an angle of #pi/2 #, vertex B has an angle of #( pi)/4 #, and the triangle's area is #45 #. What is the area of the triangle's incircle?
 A triangle has vertices A, B, and C. Vertex A has an angle of #pi/2 #, vertex B has an angle of #( pi)/4 #, and the triangle's area is #2 #. What is the area of the triangle's incircle?
 A triangle has corners at #(9 ,5 )#, #(2 ,3 )#, and #(7 ,4 )#. What is the area of the triangle's circumscribed circle?
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