How do you graph #x+4y=-8#?

Answer 1

see explanation below

#x + 4y = -8#
check #x-#intercept when #y =0# #x + 4(0) = -8# #x = -8# therefore, #x-# intercept at #(-8,0)#
check #y-#intercept, when #x =0# #0 + 4y = -8# #4y = -8# #y = -8/4 = -2# therefore, #y-# intercept at #(0, -2)#

mark these 2 points of intercept and make a straight line through these 2 points.

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Answer 2

To graph the equation ( x + 4y = -8 ), you can rearrange it to solve for ( y ) and then plot points. First, subtract ( x ) from both sides to isolate ( 4y ), yielding ( 4y = -x - 8 ). Then, divide both sides by 4 to solve for ( y ), resulting in ( y = -\frac{1}{4}x - 2 ). After finding the slope-intercept form, you can choose a few values of ( x ), calculate the corresponding values of ( y ), and plot the points on a coordinate plane. Finally, draw a straight line passing through these points to graph the equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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