# How do you graph #x + 4y = -4# by plotting points?

See a solution process below:

For a linear equation we can plot two points and then draw a line through the points to graph the line.

We can now plot the two points on the graph:

graph{(x^2+(y+1)^2-0.025)((x+4)^2+y^2-0.025)=0}

Now we can draw a line through the points to graph the line:

graph{(x+4y+4)(x^2+(y+1)^2-0.025)((x+4)^2+y^2-0.025)=0}

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To graph the equation x + 4y = -4 by plotting points, you can choose values for x and solve for y, or choose values for y and solve for x. Once you have pairs of x and y values, plot them on a coordinate plane and draw a line through the points. Repeat this process until you have enough points to accurately represent the line. Alternatively, you can rewrite the equation in slope-intercept form (y = mx + b) to determine the slope and y-intercept, then plot those points to graph the line.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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