How do you graph #x= -3(y-5)^2 +2#?
The graph is an "n" shape . From the equations alone, we can tell for sure that this is a quadratic equation (either "u" or "n" shaped).
Finding intersections :
You should get something like this (scroll on the graph to get a better view):
PS: Feel free to ask away any questions.
graph{-3x^2+30x-73 [-11.25, 11.25, -5.625, 5.625]} :
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To graph the equation (x = -3(y - 5)^2 + 2), follow these steps:
- Identify the vertex of the parabola, which is in the form ( (h, k) ).
- Determine the direction of the parabola, either opening upwards or downwards.
- Plot the vertex and use the direction to sketch the parabola.
- Optional: Find additional points by plugging in values for ( y ) to get corresponding ( x ) values.
- Draw the graph accordingly.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- What is the vertex, axis of symmetry, the maximum or minimum value, and the range of parabola #f(x)=x^2 -2x -15#?
- How do you solve for d in #n= (dh)/(f+d)#?
- How do you find the zeros of # y = -x^2 +32x + 19 # using the quadratic formula?
- How do you graph #F(x)=x^2-6x+8#?

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