How do you graph #(x-3)^3 + (y+2)^2 = 4# on a coordinate graph?

Answer 1

Refer to explanation

This is a circle .The general formula is

#(x-x_o)^2+(y-y_o)^2=R^2# where #(x_o,y_o)# is the cirlce centre and R is the radius.
In our case the centre of circle is #(3,-2)# and the radius is R=2

Hence the graph is graph{(x-3)^2+(y+2)^2=4 [-8.89, 8.885, -4.444, 4.44]}

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Answer 2

To graph the equation (x-3)^3 + (y+2)^2 = 4 on a coordinate graph:

  1. Recognize that this equation represents an ellipse.
  2. Determine the center of the ellipse, which is (3, -2).
  3. Calculate the length of the major axis and minor axis.
  4. Plot the center point (3, -2) on the graph.
  5. Use the calculated length of the major and minor axes to draw the ellipse symmetrically around the center point.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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