How do you graph #x+2y=8# using intercepts?

Question

Hazel Anglin · Accepted Answer

The x-intercept is #(8,0)#.

The y-intercept is #(0,4)#.

Graph: #x+2y=8# The x-intercept is the value of #x# when #y=0#. The y-intercept is the value of #y# when #x=0#. To get the x-intercept, substitute #0# for #y#. #x+(2*0)=8# #x=8# The x-intercept is #(8,0)#. To get the y-intercept, substitute #0# for #x#. #0+2y=8# #2y=8# Divide by #2#. #y=4# The y-intercept is #(0,4)#. You now have two points on the line. You can plot them and then draw a straight line through the points. graph{x+2y=8 [-12.55, 12.76, -5.42, 7.24]}

Kennedy Adams · Answer

undefined To graph $x + 2y = 8$ using intercepts:

1. Find the x-intercept by setting y = 0 and solving for x: 
   $x + 2(0) = 8 \Rightarrow x = 8$
   The x-intercept is (8, 0).

2. Find the y-intercept by setting x = 0 and solving for y:
   $0 + 2y = 8 \Rightarrow y = 4$
   The y-intercept is (0, 4).

Plot the x-intercept at (8, 0) and the y-intercept at (0, 4), then draw a straight line through these two points to graph the equation $x + 2y = 8$.

Julia Adams · Answer

undefined To graph the equation $x + 2y = 8$ using intercepts:

1. To find the x-intercept, set $y = 0$ and solve for $x$.
$$x + 2(0) = 8$$
$$x = 8$$

2. To find the y-intercept, set $x = 0$ and solve for $y$.
$$0 + 2y = 8$$
$$2y = 8$$
$$y = 4$$

3. Plot the x-intercept at (8, 0) and the y-intercept at (0, 4).

4. Draw a straight line passing through these two points.

That's it. You have graphed the equation $x + 2y = 8$ using intercepts.