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How do you graph #x + 2y = -2#?

Answer 1

Eli Assouline

Convert the equation to slope-intercept form by solving for #y#.

#x+2y=-2#

(Subtract #x# from both sides.)

#2y=-2-x#

(Split both sides in half.)

#(cancel (2)y)/(cancel (2))=(-cancel (2))/(cancel (2))-(x)/(2)#

#y=(-x)/(2)-1#

Values for #x# and #y#: #x=-2, y=0# #x=0, y=-1# #x=2, y=-2#

plot{y=-x/2-1 [-8.03, 6.03, -3.945, 3.085]}

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Answer 2

Isaiah Anthony

To graph the equation ( x + 2y = -2 ), first solve for ( y ) to express it in terms of ( x ):

[ 2y = -x - 2 ] [ y = -\frac{1}{2}x - 1 ]

Now, plot the y-intercept at ( y = -1 ), then use the slope ( -\frac{1}{2} ) to find another point, and draw a straight line passing through both points.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.