How do you graph #x^2+y^2=25#?

Answer 1

Below

The general formula of a circle is given by: #(x-h)^2+(y-k)^2=r^2# where #(h,k)# is the centre is r is the radius
Therefore, #x^2+y^2=25# can also be written as #(x-0)^2+(y-0)^2=5^2#
We can immediately see that the centre is #(0,0)# and the radius is 5

The graph is drawn below graph{x^2+y^2=25 [-10, 10, -5, 5]}

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Answer 2

To graph the equation (x^2 + y^2 = 25), which represents a circle with radius 5 and centered at the origin, follow these steps:

  1. Plot the center of the circle at the origin (0, 0).
  2. Since the equation represents all points whose distances from the origin are 5 units (radius of the circle), mark points on the circle accordingly.
  3. To find points on the circle, you can choose various values for (x) or (y), and then calculate the corresponding values to satisfy the equation.
  4. For example, if you let (x = 0), then (y) can be (\pm 5). Similarly, if you let (y = 0), then (x) can be (\pm 5).
  5. Connect the plotted points to form the circle.

Once these steps are completed, you'll have the graph of (x^2 + y^2 = 25), which is a circle with radius 5 centered at the origin.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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