How do you graph #x^2+y^2-1=0#?

Answer 1

Wyatt Anderson

#x^2+y^2-1=0# is a circle with center at the origin and radius #1#

#x^2+y^2-1=0color(white)("XX")rArrcolor(white)("XX")x^2+y^2=1^2#

Any equation of the form #x^2+y^2=r^2# is a circle with center at the origin i.e. at #(0,0)# with a radius of #r#

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Answer 2

Evelyn Arboleda

To graph the equation (x^2 + y^2 - 1 = 0):

Recognize that this equation represents a circle with a radius of 1 unit and a center at the origin (0, 0).
Plot the center of the circle at the point (0, 0).
Use the radius of 1 unit to plot additional points on the circle. You can use points such as (1, 0), (-1, 0), (0, 1), and (0, -1).
Connect these points to form the circle.

The graph of (x^2 + y^2 - 1 = 0) will be a circle with a radius of 1 unit centered at the origin.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.