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How do you graph using the intercepts for #10x+8y=2#?

Answer 1

Eli Assouline

x-intercept #= (1/5)#, y-intercept #= (1/4)#

#x/a + y./b =1# where a is the x-intercept and b the y-intercept.

#10x + 8y = 2#

#(10/2)x + (8/2)y = 1#

#x /(1/5) + y/(1/4) = 1#

x-intercept #= (1/5)#, y-intercept #= (1/4)#

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Answer 2

Eva Adamson

To graph the equation (10x + 8y = 2) using intercepts:

Find the x-intercept by setting (y = 0) and solving for (x). (10x + 8(0) = 2) (10x = 2) (x = \frac{2}{10} = 0.2)
Find the y-intercept by setting (x = 0) and solving for (y). (10(0) + 8y = 2) (8y = 2) (y = \frac{2}{8} = 0.25)

Plot the points (0.2, 0) and (0, 0.25), then draw a line passing through both points.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.