How do you graph this linear inequality #x + 2y<= 5#?
I would plot it as a normal line and then choose the area below the line as:
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To graph the linear inequality (x + 2y \leq 5), follow these steps:
- First, graph the boundary line (x + 2y = 5).
- To graph the boundary line, find two points that satisfy the equation.
- Let's choose (x = 0), then (2y = 5), so (y = 2.5). One point is (0, 2.5).
- Let's choose (y = 0), then (x = 5). Another point is (5, 0).
- Plot these two points and draw a straight line passing through them. This line represents the boundary of the inequality.
- Since the inequality is (\leq), we need to determine which side of the line to shade.
- To determine the shading, pick a test point not on the boundary line. The origin (0,0) is a convenient choice.
- Substitute the coordinates of the test point into the original inequality: (0 + 2(0) \leq 5).
- Simplify to determine if the inequality is true or false. In this case, it's true.
- Shade the region containing the test point. If the inequality were false, shade the opposite region.
The shaded region represents the solution set of the inequality.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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