How do you graph this linear inequality #x + 2y<= 5#?

Answer 1

I would plot it as a normal line and then choose the area below the line as:

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Answer 2

To graph the linear inequality (x + 2y \leq 5), follow these steps:

  1. First, graph the boundary line (x + 2y = 5).
  2. To graph the boundary line, find two points that satisfy the equation.
  3. Let's choose (x = 0), then (2y = 5), so (y = 2.5). One point is (0, 2.5).
  4. Let's choose (y = 0), then (x = 5). Another point is (5, 0).
  5. Plot these two points and draw a straight line passing through them. This line represents the boundary of the inequality.
  6. Since the inequality is (\leq), we need to determine which side of the line to shade.
  7. To determine the shading, pick a test point not on the boundary line. The origin (0,0) is a convenient choice.
  8. Substitute the coordinates of the test point into the original inequality: (0 + 2(0) \leq 5).
  9. Simplify to determine if the inequality is true or false. In this case, it's true.
  10. Shade the region containing the test point. If the inequality were false, shade the opposite region.

The shaded region represents the solution set of the inequality.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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