How do you graph the system #y > -3x+3# and #y>x+2#?
(1) y > - 3x + 3
(2) y > x + 2
Graph the Line (1) first, y = - 3x + 3. The area above the line represents the solution to inequality (1), so color or shade it. Graph the Line (2) next, y = x + 2. The area above this Line (2) represents the compound solution set, which is the area that is shared by all. graph{-3x + 3 [-10, 10, -5, 5]} graph{x + 2 [-10, 10, -5, 5]}
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To graph the system of inequalities y > -3x + 3 and y > x + 2, you would first graph the lines y = -3x + 3 and y = x + 2. Then, you would shade the region above both lines, since the inequalities indicate that y is greater than both expressions. The shaded region where both inequalities are satisfied is the solution to the system.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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