How do you graph the system of linear inequalities #y2x-7# and #4x+4y

Question

How do you graph the system of linear inequalities #y>2x-7# and #4x+4y<-12#?

Avery Alexander · Accepted Answer

Plot the two lines. The solution is the set of points between them. The lines should be dotted (not included in the solution) and the space between the lines shaded.

Arrange the equations into standard format (y < ax + b). Calculate and plot some points. Check for the solution range for each inequality. Locate the common solution space for both inequalities.

Julia Adams · Answer

undefined To graph the system of linear inequalities $y > 2x - 7$ and $4x + 4y < -12$: 1. Graph the boundary lines for each inequality: - For $y > 2x - 7$, graph the line $y = 2x - 7$, but use a dashed line because it's a strict inequality (does not include the line itself). - For $4x + 4y < -12$, graph the line $4x + 4y = -12$, but again use a dashed line because it's a strict inequality. 2. Choose a test point not on the boundary lines and plug it into each inequality to determine which region to shade: - For example, the origin (0,0) is a common test point. - For $y > 2x - 7$, if (0,0) satisfies the inequality, shade the region above the line; if not, shade the region below the line. - For $4x + 4y < -12$, if (0,0) satisfies the inequality, shade the region on the same side as the origin; if not, shade the region on the opposite side. 3. The intersection of the shaded regions represents the solution set for the system of inequalities.

How do you graph the system of linear inequalities #y&gt;2x-7# and #4x+4y&lt;-12#?

How do you graph the system of linear inequalities #y>2x-7# and #4x+4y<-12#?