How do you graph the quadratic function and identify the vertex and axis of symmetry for #y=-(x-2)^2-1#?
This has no real solutions hence there are no x-intercepts.
Knowing the ' shape' of the parabola, the vertex and the y-intercept enables the graph to be sketched. graph{-(x-2)^2-1 [-10, 10, -5, 5]}
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To graph the quadratic function ( y = -(x-2)^2-1 ) and identify the vertex and axis of symmetry:
- Plot the vertex at the point (2, -1).
- Since the coefficient of ( x^2 ) is negative, the parabola opens downwards.
- The axis of symmetry is the vertical line passing through the vertex, which is ( x = 2 ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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