How do you graph the linear inequality #y>=-x-3#?

Answer 1

Refer to the explanation.

Graph:

#y>=-x-3#

Determine a few points on the line. (Only two are necessary.)

#x=-2,##y=-1##color(white)(..) ##"Point:"##(-2,-1)#
#x=0,##y=-3##color(white)(..) ##"Point:"##(0,-3)#
#x=2,##y=-5##color(white)(..) ##"Point:"##(2,-5)#

Plot the points and draw a solid, straight line through them to represent the equality. Then shade in the area above the line to represent the inequality.

graph{y>=-x-3 [-15.22, 16.81, -10.12, 5.9]}

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Answer 2

To graph the linear inequality ( y \geq -x - 3 ), follow these steps:

  1. Begin by graphing the boundary line ( y = -x - 3 ) as a dashed line, since the inequality is not strict (( \geq )).
  2. Choose a test point not on the boundary line. The origin (0,0) is a common choice.
  3. Substitute the coordinates of the test point into the original inequality.
  4. If the inequality holds true, shade the region containing the test point. If not, shade the opposite region.
  5. Since the inequality is ( \geq ), include the boundary line in the shaded region.

The graph should show a shaded region above and including the line ( y = -x - 3 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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