How do you graph the line #y = 2x + 5#?

Answer 1

#"see explanation"#

#"one way is to find the intercepts, that is where the graph"# #"crosses the x and y axes"#
#• " let x = 0, in the equation for y-intercept"#
#• " let y = 0, in the equation for x-intercept"#
#x=0rArry=0+5=5larrcolor(red)"y-intercept"#
#y=0rArr2x+5=0rArrx=-5/2larrcolor(red)"x-intercept"#
#"plot the points "(0,5)" and "(-5/2,0)#
#"draw a straight line through them for graph"# graph{(y-2x-5)((x-0)^2+(y-5)^2-0.04)((x+5/2)^2+(y-0)^2-0.04)=0 [-10, 10, -4, 6]}
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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