How do you graph the inequality #y>x+12#?
See a solution process below:
First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.
We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.
graph{(x^2+(y-12)^2-0.25)((x+12)^2+y^2-0.25)(y-x-12)=0 [-30, 30, -15, 15]}
Now, we can shade the left side of the line.
However, we need to change the boundary line to a dashed line because the inequality operator does not contain an "or equal to" clause.
graph{(y-x-12) > 0 [-30, 30, -15, 15]}
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To graph the inequality ( y > x + 12 ), first graph the line ( y = x + 12 ) as a dashed line. Then, shade the region above the line, as the inequality states that ( y ) is greater than ( x + 12 ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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