How do you graph the inequality #x+2y > -8#?

Bring the inequality to standard form: f(x,y) = x + 2y + 8 > 0 First, graph the Line x + y - 8 = 0 by its 2 intercepts. Make x = 0, y-intercept --> 2y = -8 --> y = -4 Make y = 0, x-intercept --> x = -8. To find the solution set, consider the the origin O's position. Replace x = 0 and y = 0 into the inequality, we get 8 > 0. It is true, then, O is located in the solution set area, that is above the Line.

To graph the inequality ( x + 2y > -8 ), follow these steps:

1. Begin by graphing the boundary line ( x + 2y = -8 ) as a solid line.
2. To find the boundary line, first solve for ( y ) in terms of ( x ): ( y = \frac{-x}{2} - 4 ).
3. Plot at least two points on the line using the coordinates from the equation.
4. Draw a solid line through the points to represent the boundary.
5. Since the inequality is ( > ), shade the region above the boundary line to indicate all the points that satisfy the inequality.