How do you graph the inequality #a + b<12#?

Answer 1

See below:

It will look like this:

graph{y<12-x [-20, 20, -15, 15]}

The shaded area is the solution.

The line has a slope of #-1#, passes through the y axis at #y=12#, and has a dotted line to indicate that the line itself is not a solution.
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Answer 2

To graph the inequality (a + b < 12):

  1. Begin by graphing the line (a + b = 12) as a solid line.
  2. Since the inequality is (<), the region below the line (a + b = 12) is the solution set.
  3. Shade the area below the line to represent the solution set.

The line (a + b = 12) can be graphed by plotting two points on the line and drawing a straight line through them. Then, shade the area below the line.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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