How do you graph the inequality #a + b<12#?
See below:
It will look like this:
graph{y<12-x [-20, 20, -15, 15]}
The shaded area is the solution.
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To graph the inequality (a + b < 12):
- Begin by graphing the line (a + b = 12) as a solid line.
- Since the inequality is (<), the region below the line (a + b = 12) is the solution set.
- Shade the area below the line to represent the solution set.
The line (a + b = 12) can be graphed by plotting two points on the line and drawing a straight line through them. Then, shade the area below the line.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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