# How do you graph the inequality #20 > 2x+2y#?

See a solution process below:

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.

graph{(x^2+(y-10)^2-0.25)((x-10)^2+y^2-0.25)(2x+2y-20)=0 [-30, 30, -15, 15]}

Now, we can shade the left side of the line. We need to also make the boundary line a dashed line because the inequality operator does not contain an "or equal to" clause.

graph{(2x+2y-20) < 0 [-30, 30, -15, 15]}

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To graph the inequality (20 > 2x + 2y), you can follow these steps:

- Rewrite the inequality in slope-intercept form: (y > -x + 10).
- Graph the boundary line (y = -x + 10) as a dashed line, since the inequality is strict (">").
- Choose a test point not on the boundary line. A common choice is the origin (0,0).
- Substitute the coordinates of the test point into the original inequality.
- If the inequality is true for the test point, shade the region that contains the test point. Otherwise, shade the opposite region.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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