How do you graph the equation #y<=2x+3#?
First, find two points which solve the this if it is written as an equation and plot these two points on the grid then draw a line through the two points:
graph{(y  2x  3)(x^2 + (y3)^2  0.125)((x  2)^2 + (y  7)^2  0.125) = 0 [20, 20, 10, 10]}
Because the inequality is "less than or equal to" we can draw a solid line through the two points. And, also because it is "less than or equal to" we need to shade below the line.
graph{(y  2x  3) <= 0 [20, 20, 10, 10]}
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To graph the inequality (y \leq 2x + 3), follow these steps:

Begin by graphing the line (y = 2x + 3) as if it were an equation.

Since the inequality is (y \leq 2x + 3), the solution includes all points on the line as well as those below it.

To indicate the area below the line, draw a dashed line to represent the boundary (y = 2x + 3).

Shade the region below the dashed line to represent the solution set.

Optionally, if the inequality includes equality ((\leq) or (\geq)), you can draw a solid line to represent the boundary instead of a dashed line.

Label the shaded area appropriately if needed.
That's how you graph the inequality (y \leq 2x + 3).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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