How do you graph the equation by plotting points x=6?
See a solution process below:
So:
These points can be plotted as:
graph{((x-6)^2+(y+10)^2-0.2)((x-6)^2+(y+5)^2-0.2)((x-6)^2+y^2-0.2)((x-6)^2+(y-10)^2-0.2)~=0 [-26, 26, -13, 13]}
At this point, we can graph the equation by drawing a line through the points:
graph{((x-6)^2+(y+10)^2-0.2)((x-6)^2+(y+5)^2-0.2)((x-6)^2+y^2-0.2)((x-6)^2+(y-10)^2-0.2)((x-6)^2+(y-5)^2-0.2)(x - 6)=0 [-26, 26, -13, 13]}
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To graph the equation x = 6, you would plot points where x is always 6 and y can take any value. This results in a vertical line passing through the point (6, y) for all y values.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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