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How do you graph #r=-4sintheta#?

Answer 1

Compute polar points then connect the points.

From #r=-4 sin theta#

Radius # r" " " #Angle #theta#
~~~~~~~~~~~~~~~~~
#0" " " " "" " " " "0#
#-1.53" " " " "pi/8#
#-2.828" " " " "pi/4#
#-3.695" " " " "(3pi)/8#
#-4" " " " "" " " " "pi/2#
#-3.695" " " " "(5pi)/8#
#-2.828" " " " "(3pi)/4#
#-1.53" " " " "(7pi)/8#
#0" " " " "" " " " "pi#
#1.5307" " " " "(9pi)/8#
#2.828" " " " "(5pi)/4#
#3.695" " " " "(11pi)/8#
#4" " " " " " " " " "(3pi)/2#
#3.695" " " " "(13pi)/8#
#2.828" " " " "(7pi)4#
#1.53" " " " "(15pi)/8#
#0" " " " " " " " " "2pi#

God bless....I hope the explanation is useful.

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Answer 2

Violet Anderson

To graph ( r = -4\sin(\theta) ), you can plot points by substituting various values of ( \theta ) and calculating the corresponding values of ( r ). Then, plot these points on a polar coordinate system. Since ( r ) is proportional to ( \sin(\theta) ), the graph will form a sinusoidal shape, but with a negative amplitude due to the negative coefficient (-4).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.