How do you graph #r=4+6costheta#?

Answer 1

See Socratic graph for the Cartesian form of the equation.

The pole is crossed by this limacon.

A dimple is the pole.

As #r = f(costheta)=f(cos(-theta)#, the graph is symmetrical about
#theta = 0#.
Maximum #r = f(0)=f(2pi)=10#.

I have applied the polar equation in its Cartesian form.

#x^2+y^2-4sqrt(x^2+y^2)-6x=0#.

x^2+y^2-4sqrt(x^2+y^2)-6x=0 [-20, 20, -10, 10]}

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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