How do you graph quadratic functions #y=x^2-4x+7#?

Answer 1

You basically need 3 sets of points:
1] y-axis intercept: setting #x=0#;
2] vertex; #x_v# and #y_v#;
3] x-axis intercepr(s): setting #y=0#
In your case:

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Answer 2

To graph the quadratic function ( y = x^2 - 4x + 7 ), you can follow these steps:

  1. Find the vertex of the parabola using the formula ( x = -\frac{b}{2a} ).
  2. Calculate the value of ( y ) at the vertex using the equation ( y = ax^2 + bx + c ).
  3. Plot the vertex on the graph.
  4. Find additional points by choosing values for ( x ) and calculating the corresponding ( y ) values using the equation.
  5. Plot these points on the graph.
  6. Draw a smooth curve through the plotted points to represent the parabola.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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