How do you graph, label the vertex, axis of symmetry and x intercepts of #y=5(x-2/5)(x-11/5)#?

Answer 1

(#13/10#,#-81/20#)
I hope this help

y=5(x-#2/5#)(x-#11/5#) 1.Apply to distributive property 2. Cancel the common factor of 5 3. Simplify #5(x-13/10)^2#-#81/20# #y=5(x-13/10)^2#-#81/20# x=#13/10#
Use the Vertex Form is y=#a(x-h)^2+k# a=5 h=#13/10# k=#-81/20#
Find the vertex (h,k) (#13/10,-81/20#) Find p with formula #1/4a# #1/4*5#=#1/20# (#13/10#,-4) x=#-41/10# Table Vertex X|Y -1|22.4 0|4.4 2|-1.6 3|10.4
Vertex: (#13/10#) Focus:(#13/10#,-4) Axis of symmetry: x= #13/10# Directrix: y=#-41/10#
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Answer 2

To graph the function ( y = 5(x - \frac{2}{5})(x - \frac{11}{5}) ):

  1. Identify the vertex using the formula ( x = \frac{-b}{2a} ).
  2. Substitute the value of the vertex's x-coordinate into the function to find the y-coordinate of the vertex.
  3. Determine the axis of symmetry, which is the vertical line passing through the vertex.
  4. Calculate the x-intercepts by setting ( y = 0 ) and solving for ( x ).
  5. Plot the vertex, axis of symmetry, and x-intercepts on the graph.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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