# How do you graph #f(x)= x^2 - 10x + 5#?

Calculating the vertex and axis' cut points of your parabola.

Since our function is a parabola, to graph it, we will need to know where its vertex is, thus, we apply the vertex calculating formula, which follows:

Let's calculate where does the function cut the OX axis by equaling the image to 0;

Knowing now the OX cut points, let's find out the OY axis ones:

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To graph the function ( f(x) = x^2 - 10x + 5 ), you can follow these steps:

- Identify the vertex using the formula ( x = -\frac{b}{2a} ), where ( a = 1 ) (coefficient of ( x^2 )) and ( b = -10 ) (coefficient of ( x )).
- Substitute the value of ( x ) obtained from step 1 into the function to find the ( y )-coordinate of the vertex.
- Find additional points by choosing values of ( x ) and calculating the corresponding ( y )-values using the function.
- Plot the points obtained in steps 1-3 on a coordinate plane.
- Draw a smooth curve passing through the plotted points to represent the graph of the function.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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