How do you graph #f(x) = 2x^2 – 2# by plotting points?

Question

Genesis Allen · Accepted Answer

#"see explanation"#

#"select values of x and substitute into equation for values of y"#

#"the x-intercepts can be found by equating f(x) to zero"#

#rArr2x^2-2=0rArr2(x^2-1)=0#

#rArr2(x-1)(x+1)=0#

#rArrx=-1 , x=1larrcolor(red)" x-intercepts"#

#f(color(red)(0))=0-2=-2rArr(0,-2)larrcolor(red)" y-intercept"#

#f(color(red)(2))=8-2=6rArr(2,6)#

#f(color(red)(-2))=8-2=6rArr(-2,6)#

Plot the other two points and the x/y intercepts, then create a graph with a smooth curve through them: graph{2x^2-2 [-10, 10, -5, 5]}

Hazel Anglin · Answer

undefined To graph f(x) = 2x^2 - 2 by plotting points, you can choose x-values, calculate the corresponding y-values using the given function, and then plot the points on a coordinate plane. You can start with a few x-values such as -2, -1, 0, 1, and 2, and find the corresponding y-values using the function. Plot these points (-2, 6), (-1, 0), (0, -2), (1, 0), and (2, 6) on the coordinate plane, then draw a smooth curve through these points to represent the graph of the function.