How do you graph by using the zeros for #f(x)=-48x^2+3x^4#?

Answer 1

Zeros at: #4 , -4 , 0 #

We need to find roots, so:

Notice that we can rewrite the expression as a quadratic:

Let #z = x^2#

Then:

#3z^2-48z=0#
Solving for #z#:
#z(3z-48)=0 => z = 0, and z=48/3 = 16#
But #z= x^2#

So:

#x^2=0=> x=0#
#x^2 = 16=> x=sqrt16=> x= +-4#
Other values can be found by putting in value for #x# and calculating corresponding values of #y#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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