How do you graph and solve #abs(x+1)+x+1<-1#?
The inequation has not solutions.
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Invalid inequality. No solution at all.
Moreover, for this to occur,
Thus, this case is also disqualified.
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To graph and solve the inequality ( |x + 1| + x + 1 < -1 ), you first solve the equation ( |x + 1| + x + 1 = -1 ) to find the boundary points. Then, you graph the solution on a number line and determine the solution set based on the inequality.
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Solve the equation ( |x + 1| + x + 1 = -1 ): ( |x + 1| + x + 1 = -1 ) ( |x + 1| = -1 - x - 1 ) ( |x + 1| = -x - 2 )
Since the absolute value of a number cannot be negative, there are no solutions for this equation.
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Graph the inequality on a number line: Since there are no solutions to the equation, there are no boundary points to graph. Therefore, the graph of the inequality ( |x + 1| + x + 1 < -1 ) is an empty set on the number line.
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Solve the inequality: Since there are no boundary points to include in the solution, the solution set for the inequality ( |x + 1| + x + 1 < -1 ) is an empty set, represented as ( \emptyset ). Therefore, there are no real solutions to the inequality.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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