How do you graph and solve #6 abs(2x + 5) >66#?
additionally
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To graph and solve the inequality ( 6 \lvert 2x + 5 \rvert > 66 ):

Graphing:
 Start by graphing the equation ( y = 6 \lvert 2x + 5 \rvert ).
 This is a Vshaped graph centered at ( x = \frac{5}{2} ), with a slope of 6 on both sides of the vertex.

Finding Critical Points:
 Set ( 6 \lvert 2x + 5 \rvert = 66 ) to find the critical points.
 Solve ( 2x + 5 = \pm \frac{66}{6} ) separately to find the critical points.
 Solve for ( x ) in each equation to find the critical points.

Testing Intervals:
 Test the intervals created by the critical points by plugging in test points into the original inequality.
 Determine which intervals satisfy the inequality.

Solving:
 Express the solution using interval notation based on the intervals where the inequality holds true.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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