# How do you graph and solve #|3x+1| + |3-2x| =11#?

Now we have two options:

a)

b)

Following with a) we have

a-1)

a-1-1)

a-1-2)

Now following with b)

b-1)

b-1-1)

b-1-2)

After checking the found values, we pick the feasible values

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To graph and solve the equation |3x+1| + |3-2x| = 11:

- Identify critical points by setting each absolute value expression equal to zero and solving for x.
- Divide the number line into intervals using these critical points.
- Test a value within each interval in the original equation to determine the sign of the expression.
- Graph the solution set on the number line.
- Solve for x in each interval to find the specific solutions.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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