How do you graph and solve #|2x+3|<=15#?
See a solution process below:
The absolute value function takes any term and transforms it to its non-negative form. Therefore, we must solve the term within the absolute value function for both its negative and positive equivalent.
First, subtract Now, divide each segment of the system by Or Or. in interval notation To graph this we will draw vertical lines at The lines will be a solid line because the inequality operators contain "or equal to" clauses. We will shade between the lines to show the interval:
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To graph and solve ( |2x+3| \leq 15 ):
- Split the inequality into two cases: a) ( 2x + 3 \leq 15 ) b) ( 2x + 3 \geq -15 )
- Solve each case for x.
- Graph the solutions on the number line.
- The solution is the intersection of the two graphs.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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