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How do you graph and solve #|2x+1|-5>7#?

Answer 1

Avery Alexander

See explanation

Given: #|2x+1|-5>7#

Add 5 to both sides

#|2x+1|>7#

Consider the case: #2x+1=7# for the CUT OFF POINT

#2x=6#

#x=6/3=2# as the curt of point

So we need all those value of #x# that are less than #-2# and greater than #+2#. This is drawn as:

But the plot of #|2x+1|>12# is:

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Answer 2

Kennedy Adams

To graph and solve the inequality ( |2x+1| - 5 > 7 ), first, isolate the absolute value expression by adding 5 to both sides of the inequality. Then, solve for ( |2x+1| ) by adding 7 to both sides. Afterward, split the inequality into two cases: one where ( 2x + 1 ) is positive and one where it's negative. Solve each case separately and then combine the solutions. Finally, graph the solution on a number line.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you graph and solve #|2x+1|-5&gt;7#?

How do you graph and solve #|2x+1|-5>7#?