How do you graph #abs(4x +8) 16#?

Question

How do you graph #abs(4x +8)> 16#?

Avery Alexander · Accepted Answer

Make a table of the points and plot them.

Whether using manual calculations and graph paper of a calculation program, at some point the calculations must be made to generate the points for the graph. The direct solution is: #|4x + 8| > 16# #|4x| > 8# ; #|x| > 2# or, x < -2 AND x > 2 For an absolute value problem the inequality can be split into two parts – one with the expression with a positive variable value, and the other with it as a negative. #4x + 8 > 16# and #4(-1)x + 8 > 16# or #-4x + 8 > 16# Solving these we obtain: #4x > 8# ; #x > 2# and #-4x > 8# ; #x < -2# (recall that dividing by a negative reverses an inequality direction). The solution is thus [-inf, -2) and (2, +inf]. The graph is a dotted line along the x = -2 and x = 2 values, with shading on the left and right sides, clear in the middle.

Jameson Allen · Answer

undefined To graph the inequality $|4x + 8| > 16$, first solve for the critical points where the expression inside the absolute value equals zero. Then, determine the intervals where the expression inside the absolute value is greater than or less than 16. Finally, graph these intervals on a number line.

How do you graph #abs(4x +8)&gt; 16#?

How do you graph #abs(4x +8)> 16#?